QUOTE (conig @ Sep 24 2008, 03:11 PM)
index.php?act=findpost&pid=11581sorry forgot about this.
pilot 40% richer. needle same main 35-40% richer. the main and pilot need the hole size enlarged 30% minimuim. so about 20% leaner then methanol your looking for 6.5-7 to 1 as a ratio.
actual hp gains no idea but i picked up 5 lengths consistently(i race almost exclusively arm drop)
heres the math i was speaking of. very cut down summed up and using a mock example motor i used.
the example motor
Gasoline is what most of our cars came setup so it's usually what we stick with. Gasoline is a mixture of hydrocarbons. The petroleum distillate fraction termed "gasoline" contains mostly saturated hydrocarbons usually with a chemical formula of C8H18. The air fuel ratio, A/F Ratio, for complete combustion is 14.7:1, stoichiometric. The A/F ratio for maximum power is approximately 12.5:1 - 12.8:1. This means that our engine at max power, 12.8:1, consumes 12.8 pounds of air for 1 pound of fuel. Gasoline has approximately 18,400 BTU/lb . Using the air flow calculator with the default inputs we get our 355 SBC consumes 567.53 cfm @ 6500rpm which is 44.34pounds of air and consumes 3.46 pounds of fuel. Therefore if we are using gasoline our engine is producing 63,664( 18,500 x 3.46) BTU's of energy at 6500 rpm
Methanol is 10,260 btu per LB and runs at 5.0-6.0 to 1 so 44.34/ 5= 8.868 lb of fuel. 8.868 x10.260=90,986 btu.
e85 is 14,021 btu per LB and runs at 7.4 to 1 so 44.34/7.4=5.95 lb of fuel. 5.95x14,021= 83,368
so basically 31% more latent heat(energy) per compression stroke for e85 and 41% more latent heat for methanol.
YOU LOST ME AT SORRY ABOUT THIS.................... LOL WOW Thats alot of info I understand that its burns hotter than fuel